Set Matrix Zeroes
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
click to show follow up.
Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement uses O(m + n) space, but still not the best solution. Could you devise a constant space solution?
URL: https://leetcode.com/problems/set-matrix-zeroes/
class Solution(object):
def setZeroes(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
if matrix == None or len(matrix) == 0:
pass
elif len(matrix) == 1 and len(matrix[0]) == 1:
pass
else:
rows_with_0 = [False]*len(matrix)
cols_with_0 = [False]*len(matrix[0])
for i in range(len(matrix)):
for j in range(len(matrix[0])):
if matrix[i][j] == 0:
rows_with_0[i] = True
cols_with_0[j] = True
for i in range(len(matrix)):
for j in range(len(matrix[0])):
if rows_with_0[i] or cols_with_0[j]:
matrix[i][j] = 0
Constant Space Solution:
class Solution(object):
def setZeroes(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
first_row = False
first_col = False
for j in range(len(matrix[0])):
if matrix[0][j] == 0:
first_row = True
for i in range(len(matrix)):
if matrix[i][0] == 0:
first_col = True
for i in range(1, len(matrix)):
for j in range(1, len(matrix[0])):
if matrix[i][j] == 0:
matrix[i][0] = 0
matrix[0][j] = 0
for i in range(1, len(matrix)):
for j in range(1, len(matrix[0])):
if matrix[i][0] == 0 or matrix[0][j] == 0:
matrix[i][j] = 0
if first_col:
for i in range(len(matrix)):
matrix[i][0] = 0
if first_row:
for i in range(len(matrix[0])):
matrix[0][i] = 0